在numpy数组中查找唯一点 [英] Finding unique points in numpy array

问题描述

在numpy数组中查找唯一的x，y点(删除重复项)的更快方法是什么:

What is a faster way of finding unique x,y points (removing duplicates) in a numpy array like:

points = numpy.random.randint(0, 5, (10,2))

我想到了将点转换为复数，然后检查唯一性的方法，但这似乎有些令人费解:

I thought of converting points to a complex numbers and then checking for unique, but that seems rather convoluted:

b = numpy.unique(points[:,0] + 1j * points[:,1])
points = numpy.column_stack((b.real, b.imag))

推荐答案

我会这样:

numpy.array(list(set(tuple(p) for p in points)))

对于大多数情况下的快速解决方案，也许此菜谱会让您感兴趣: http://code.activestate.com/recipes/52560-从序列中删除重复项/

For the fast solution in the most general case, maybe this recipe would interest you: http://code.activestate.com/recipes/52560-remove-duplicates-from-a-sequence/

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