python:不支持图像的OpenCV深度(CV_64F) [英] python: OpenCV depth of image unsupported (CV_64F)

问题描述

因此，我正在尝试使用此代码显示仅黑白图像的二进制图片:

So, I'm trying to show a binary picture with only black and white using this code:

import cv2
import numpy as np

x_img = cv2.imread("lenac.tif")

x_img_g = cv2.cvtColor(x_img, cv2.COLOR_BGR2GRAY)

y = x_img_g > 128

cv2.imshow("", y*1.0)
cv2.waitKey(0)
cv2.destroyAllWindows()

但是我遇到了这个错误:

But I'm getting this error:

>Traceback (most recent call last):
File "ex5.py", line 11, in <module>
cv2.imshow("", y*1.0)
cv2.error: OpenCV(4.0.0) c:\projects\opencv- 
python\opencv\modules\imgproc\src\color.hpp:261: error: (-2:Unspecified 
error) >in function '__cdecl cv::CvtHelper<struct 
cv::Set<1,-1,-1>,struct cv::Set<3,4,-1>,struct 
cv::Set<0,2,5>,2>::CvtHelper(const class cv::_InputArray &,const class 
cv::_OutputArray &,int)'
>Unsupported depth of input image:
>     'VDepth::contains(depth)'
> where
>     'depth' is 6 (CV_64F).

推荐答案

尝试cv2.imshow("", y.astype('float32')) 或cv2.imshow("", y.astype('uint8') * 255)

CV_64F表示numpy数组'dtype'为64位浮点 opencv仅适用于"float32"(32位浮点)，其中imshow的图像范围为0.0-1.0或"uint8"(无符号8位)0-255

CV_64F means the numpy array 'dtype' is 64bit floating-point opencv only works with 'float32' (32-bit floating point) where image range for imshow is 0.0-1.0 or 'uint8' (unsigned 8-bit) 0-255

由于y是布尔值，所以转换为数字意味着将True转换为1

Since y was a bool, converting to a number means converting True to 1

对于float32，这很好，因为显示范围最大为1

for float32, that is fine because 1 is max for imshow range

如果使用uint8，则意味着您尝试显示几乎不可见的值1/255的像素，因此您可以乘以255以使这些像素达到最大值并显示为亮白色像素

if you use uint8, that means your trying to display pixels of value 1/255 which will be barely visible, so you can multiply by 255 to bring those pixels to max and appear as bright white pixels

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