如何迭代矩阵的列? [英] How to iterate over columns of a matrix?

问题描述

在python中，如果有定义:

In python if a define:

a = arange(9).reshape(3,3)

作为3x3矩阵并进行迭代:

as a 3x3 matrix and iterate:

for i in a:

它将遍历矩阵的行.有什么办法可以遍历列吗?

It'll iterate over the matrix's rows. Is there any way to iterate over columns?

推荐答案

如何

for i in a.transpose():

或更短:

for i in a.T:

这看起来很昂贵，但实际上却很便宜(它返回对相同数据的视图，但是其shape和stride属性已置换).

This may look expensive but is in fact very cheap (it returns a view onto the same data, but with the shape and stride attributes permuted).

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