如何使用Python读取目录中的wav文件? [英] How to read only wav files in a directory using Python?

问题描述

from scipy.io.wavfile import read
files = [f for f in os.listdir('.') if os.path.isfile(f)]
print files
for i in range(0,1):
w = read(files[i])
print w

我只需要从python工作目录中读取.wav文件.并将每个.wav文件存储为一个numpy数组.这是我的代码.但是在这段代码中，所有文件都被读取.我只读取目录中的wav文件吗?怎么可能?

I need to read only .wav files from python working directory. And store the each .wav files as a numpy array. This is my code. But in this code all files are read. I only read the wav files in the directory? How it possible?

推荐答案

使用glob模块并向其传递一个模式(例如*.wav或任何命名的文件).它将返回符合条件或模式的文件列表.

Use the glob module and pass to it a pattern (like *.wav or whatever the files are named). It will return a list of files that match the criteria or the pattern.

import glob
from scipy.io.wavfile import read

wavs = []
for filename in glob.glob('*.wav'):
    print(filename)
    wavs.append(read(filename))

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