python numpy savetxt [英] python numpy savetxt
本文介绍了python numpy savetxt的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
有人可以在这里指出我在做什么错吗?
Can someone indicate what I am doing wrong here?
import numpy as np
a = np.array([1,2,3,4,5],dtype=int)
b = np.array(['a','b','c','d','e'],dtype='|S1')
np.savetxt('test.txt',zip(a,b),fmt="%i %s")
输出为:
Traceback (most recent call last):
File "loadtxt.py", line 6, in <module>
np.savetxt('test.txt',zip(a,b),fmt="%i %s")
File "/Users/tom/Library/Python/2.6/site-packages/numpy/lib/io.py", line 785, in savetxt
fh.write(format % tuple(row) + '\n')
TypeError: %d format: a number is required, not numpy.string_
推荐答案
您需要以其他方式构造数组:
You need to construct you array differently:
z = np.array(zip([1,2,3,4,5], ['a','b','c','d','e']), dtype=[('int', int), ('str', '|S1')])
np.savetxt('test.txt', z, fmt='%i %s')
when you're passing a sequence, savetext
performs asarray(sequence)
call and resulting array is of type |S4
, that is all elements are strings! that's why you see this error.
这篇关于python numpy savetxt的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文