四舍五入到最接近的步长 [英] Round in numpy to Nearest Step

问题描述

我想知道如何将numpy中的数字四舍五入到上限或下限，这是预定义步长的函数.希望以更清楚的方式说明，如果我的数字是123，步长等于50，则需要将123舍入到150或100(在这种情况下为100)中最接近的值.但我想知道是否有更好，更简洁的方法.

I would like to know how I can round a number in numpy to an upper or lower threshold which is function of predefined step size. Hopefully stated in a clearer way, if I have the number 123 and a step size equal to 50, I need to round 123 to the closest of either 150 or 100, in this case 100. I came out with function below which does the work but I wonder if there is a better, more succint, way to do this.

预先感谢

保罗

def getRoundedThresholdv1(a, MinClip):
    import numpy as np
    import math
    digits = int(math.log10(MinClip))+1
    b = np.round(a, -digits)
    if b > a:  # rounded-up
        c = b - MinClip
        UpLow = np.array((b,c))
    else:  # rounded-down
        c = b + MinClip
        UpLow = np.array((c,b))
    AbsDelta = np.abs(a - UpLow)
    return UpLow[AbsDelta.argmin()]




getRoundedThresholdv1(143, 50)

推荐答案

我认为您不需要numpy:

def getRoundedThresholdv1(a, MinClip):
    return round(float(a) / MinClip) * MinClip

此处a是单个数字，如果要向量化此功能，则只需将round替换为np.round，将float(a)替换为np.array(a, dtype=float)

here a is a single number, if you want to vectorize this function you only need to replace round with np.round and float(a) with np.array(a, dtype=float)

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