我们如何在python中读取16个无符号整数(16 uint)jpeg文件 [英] How we can read 16 un signed integer(16 uint) jpeg files in python

问题描述

我们如何在python中读取16个uint jpeg图像 请向我建议可以在python中读取这些类型文件的库. 我尝试了matplotlib，scipy，scikit-image，medpy，Pil，opencv，numpy库. 当我们使用这些库时，我的输出结果为:

How we can read the 16 uint jpeg images in python please suggest me the libraries which can read the these type of files in python. i tried matplotlib, scipy, scikit-image, medpy ,Pil ,opencv, numpy libraries. when we are using these libraries i am getting the out put as:

raise IOError("cannot identify image file")

IOError: cannot identify image file

请帮助我

从链接中找到文件

https://drive.google.com/file/d/0B4l5GiM7kBXraDEyMXdseENfUlE/edit?usp = sharing

推荐答案

具有16位JPEG图像听起来有些奇怪，因为JPEG标准不支持16位图像.不过，它具有12位图像.不幸的是，大多数阅读器仅支持普通的8位/像素RGB图像，因此即使使用12位图像，这也可能有些挑战.

Having 16-bit JPEG images sounds a bit strange, as the JPEG standard does not support 16-bit images. It has 12-bit images, though. Unfortunately, most readers only support the usual 8-bits/pixel RGB images, so even with the 12-bit images this may be a bit challenging.

一个有用的测试可以尝试:

One useful test could be to try:

hdr = open("myimage.jpeg", "rb").read(2)
print "{:02x} {:02x}".format(ord(hdr[0]), ord(hdr[1]))

如果您的文件是JPEG文件，则应以以下开头:

If your file is a JPEG file, it should start with:

ff d8

如果您没有得到这些文件，那么该文件就是其他文件.有什么程序可以用来打开文件?哪个程序生成文件?

If you do not get those, then the file is something else. Is there any program you can use to open the file? Which program produced the files?

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