如何使用numpy.all()或numpy.any()? [英] How to use numpy.all() or numpy.any()?
问题描述
我正在尝试在2D numpy数组中搜索特定值,get_above方法返回字符'initial char'上方的坐标列表
I am trying to search in a 2D numpy array for a specific value, the get_above method returns a list of coordinates above the character 'initial char'
def get_above(current, wordsearch):
list_of_current_coords = get_coords_current(current, wordsearch)
#print(list_of_current_coords)
length = len(list_of_current_coords)
first_coords = []
second_coords = []
for x in range(length):
second = list_of_current_coords[x][1]
new_first = list_of_current_coords[x][0] - 1
first_coords.append(new_first)
second_coords.append(second)
combined = [first_coords, second_coords]
above_coords = []
for y in range(length):
lst2 = [item[y] for item in combined]
above_coords.append(lst2)
return above_coords
def search_above(initial_char, target, matrix):
above_coords = get_above(initial_char, matrix)
length = len(above_coords)
for x in range(length):
if matrix[above_coords[x]] == target:
print(above_coords[x])
else:
print('not found')
调用函数时出现此错误:
And I get this error when calling the function:
ValueError:具有多个元素的数组的真值不明确.使用a.any()或a.all()
ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
任何帮助将不胜感激!
推荐答案
ValueError是由if
语句中的数组比较引起的.
The ValueError is caused by an array comparison in the if
statement.
让我们做一个更简单的测试用例:
Lets make a simpler test case:
In [524]: m=np.arange(5)
In [525]: if m==3:print(m)
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-525-de75ce4dd8e2> in <module>()
----> 1 if m==3:print(m)
ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
In [526]: m==3
Out[526]: array([False, False, False, True, False], dtype=bool)
m==3
测试产生一个布尔数组.不能在if
上下文中使用.
The m==3
test produces a boolean array. That can't be used in an if
context.
any
或all
可以将该数组压缩为一个标量布尔值:
any
or all
can condense that array into one scalar boolean:
In [530]: (m==3).any()
Out[530]: True
In [531]: (m==3).all()
Out[531]: False
所以在
if matrix[above_coords[x]] == target:
print(above_coords[x])
查看matrix[above_coords[x]] == target
,并准确确定应如何将其转换为标量True/False值.
look at matrix[above_coords[x]] == target
, and decide exactly how that should be turned into a scalar True/False value.
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