点积与字典 [英] Dot product with dictionaries

问题描述

我正在尝试将两个字典的值做点积.例如:

I am trying to do a dot product of the values of two dictionaries. For example:

dict_1={'a':2, 'b':3, 'c':5, 'd':2}
dict_2={'a':2, 'b':2, 'd':3, 'e':5 }

以列表形式，上面看起来像这样:

In list form, the above looks like this:

dict_1=[2,3,5,2,0]
dict_2=[2,2,0,3,5]

具有相同键的字典的点积将导致:

The dot product of the dictionary with the same key would result in:

Ans= 16  [2*2 + 3*2 + 5*0 + 2*3 + 0*5]

如何用字典来做到这一点?使用该列表，我可以调用np.dot函数或编写一个小循环.

How can I achieve this with the dictionary? With the list, I can just invoke the np.dot function or write a small loop.

推荐答案

在通过对dict_2进行迭代的dict_1键与get()函数结合使用的列表中使用sum函数:

Use sum function on list produced through iterate dict_1 keys in couple with get() function against dict_2:

dot_product = sum(dict_1[key]*dict_2.get(key, 0) for key in dict_1)

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