检查numpy数组行是否小于下一个 [英] Check whether numpy array row is smaller than the next

问题描述

假设我有以下数组:

In [1]: k
Out[1]: 
array([[0],
       [1],
       [2],
       [7],
       [4],
       [5],
       [6]])

我想检查k的每一行是否小于下一行.

I would like to check whether each row of k is smaller than the next.

我尝试了以下操作，但没有用:

I tried the following but it did not work:

In [2]: k[:,0]<k[:+1,0]
Out[2]: array([False, False, False, False, False, False, False], dtype=bool)

我在这里想念什么?

推荐答案

您还可以沿轴0使用np.diff并检查结果是否大于0.

You can also use np.diff along axis 0 and check whether the result is greater than 0.

arr = np.array([[0],
                [1],
                [2],
                [7],
                [4],
                [5],
                [6]])
np.diff(arr, axis=0) > 0

array([[ True],  1 > 0
       [ True],  2 > 1
       [ True],  7 > 2
       [False],  4 > 7
       [ True],  5 > 4
       [ True]]) 6 > 5

在[6]之后没有行，因此结果短了一行.

There is no row follow [6] and thus the result is one row shorter.

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