如何基于对象字符串属性在Xcode中设置条件断点? [英] How to set a conditional breakpoint in Xcode based on an object string property?

问题描述

我希望调试器在达到特定的字符串匹配时能够中断.例如，我可能会遇到这样的情况:

I'm looking to be able to have the debugger break when it reaches a particular string match. As an example, I might have something like this:

Foo myObj = [self gimmeObj];

myObj可能具有一个称为name的属性.我希望调试器在以下情况下停止执行任务:

myObj might have a property called name. I want the debugger to stop on the assignment when

[myObj.name isEqualToString:@"Bar"];

如何在Xcode中设置条件断点来做到这一点?

How can I set my conditional breakpoint in Xcode to do that?

推荐答案

您可以通过正常设置断点来在Xcode中设置条件断点，然后按住Control键单击并选择Edit Breakpoint(选择Run-> Show->断点).

You can set a conditional break point in Xcode by setting the breakpoint normally, then control-click on it and select Edit Breakpoint (choose Run -> Show -> Breakpoints).

在断点条目中，有一个条件"列.

In the breakpoint entry, there is a Condition column.

现在，要记住一些要考虑的问题.首先，gdb不了解点语法，因此必须使用[myObj name](除非name是ivar)代替myObj.name.

Now, there are several issues to keep in mind for the condition. Firstly, gdb does not understand dot syntax, so instead of myObj.name, you must use [myObj name] (unless name is an ivar).

接下来，与gdb中的大多数表达式一样，您必须告诉它返回结果的类型，即"BOOL".因此，将条件设置为:

Next, as with most expressions in gdb, you must tell it the type of return result, namely "BOOL". So set a condition like:

(BOOL)[[myObj name] isEqualToString:@"Bar"]

通常，通过临时添加类似以下代码的代码实际上更容易做到这一点:

Often it is actually easier to just do this in code by temporarily adding code like:

if ( [myObj.name isEqualToString:@"Bar"] ) {
    NSLog( @"here" );
}

，然后在NSLog上设置断点.然后，您的条件可以任意复杂，而不必担心gdb可以解析和不能解析的内容.

and then setting the break point on the NSLog. Then your condition can be arbitrarily complex without having to worry about what gdb can and can't parse.

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