Objective-C:-[NSString wordCount] [英] Objective-C: -[NSString wordCount]

问题描述

以下NSString类别方法的简单实现是什么，该方法返回self中的单词数，其中单词由任意数量的连续空格或换行符分隔?另外，字符串将少于140个字符，因此，在这种情况下，我更喜欢简单性&易读性，但会牺牲一些性能.

What's a simple implementation of the following NSString category method that returns the number of words in self, where words are separated by any number of consecutive spaces or newline characters? Also, the string will be less than 140 characters, so in this case, I prefer simplicity & readability at the sacrifice of a bit of performance.

@interface NSString (Additions)
- (NSUInteger)wordCount;
@end

我找到了以下解决方案:

I found the following solutions:

• -[NSString wordCount]的实现
• -[NSString wordCount]的实现-似乎更简单

• implementation of -[NSString wordCount]
• implementation of -[NSString wordCount] - seems a bit simpler

但是，有没有更简单的方法?

But, isn't there a simpler way?

推荐答案

像我在问题中给出的第二个链接仍然占据统治地位，因为它不仅速度最快，而且事后看来，也是相对简单的

Looks like the second link I gave in my question still reigns as not only the fastest but also, in hindsight, a relatively simple implementation of -[NSString wordCount].

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