如何使用NSRegularExpression或Objective-C中的任何其他有效方式来检查GUID(或UUID)的有效性 [英] How to check the validity of a GUID (or UUID) using NSRegularExpression or any other effective way in Objective-C
本文介绍了如何使用NSRegularExpression或Objective-C中的任何其他有效方式来检查GUID(或UUID)的有效性的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如果NSString类似于@"{A5B8A206-E14D-429B-BEB0-2DD0575F3BC0}",则该方法应返回TRUE,而对于@@"bla bla bla"这样的NSString则返回FALSE.
The method should return TRUE if the NSString is something like @"{A5B8A206-E14D-429B-BEB0-2DD0575F3BC0}" and FALSE for a NSString like @"bla bla bla"
我正在使用类似的东西:
I am using something like:
- (BOOL)isValidGUID {
NSError *error;
NSRange range = [[NSRegularExpression regularExpressionWithPattern:@"(?:(\\()|(\\{))?\\b[A-F0-9]{8}(?:-[A-F0-9]{4}){3}-[A-Z0-9]{12}\\b(?(1)\\))(?(2)\\})" options:NSRegularExpressionCaseInsensitive error:&error] rangeOfFirstMatchInString:self.GUID options:0 range:NSMakeRange(0, [self.GUID length])];
if (self.GUID && range.location != NSNotFound && [self.GUID length] == 38) {
return TRUE;
} else {
return NO;
}
}
但是它没有按我预期的那样工作.
but it is not working as I have expected.
重要:我正在使用的GUID用大括号括起来,例如:{A5B8A206-E14D-429B-BEB0-2DD0575F3BC0}
Important: GUID which I am using is enclosed by curly braces like this: {A5B8A206-E14D-429B-BEB0-2DD0575F3BC0}
推荐答案
此正则表达式与我匹配
\A\{[A-F0-9]{8}-[A-F0-9]{4}-[A-F0-9]{4}-[A-F0-9]{4}-[A-F0-9]{12}\}\Z
简而言之:
-
\A
和\Z
是字符串的开头和结尾 -
\{
和\}
被逃脱了卷曲的bracets -
[A-F0-9]{8}
正好是0、1、2、3、4、5、6、7、8、9,A,B,C,D,E,F的8个字符
\A
and\Z
is the beginning and end of the string\{
and\}
is escaped curly bracets[A-F0-9]{8}
is exactly 8 characters of either 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F
作为NSRegularExpression,它看起来像这样
As an NSRegularExpression it would look like this
NSError *error = NULL;
NSRegularExpression *regex =
[NSRegularExpression regularExpressionWithPattern:@"\\A\\{[A-F0-9]{8}-[A-F0-9]{4}-[A-F0-9]{4}-[A-F0-9]{4}-[A-F0-9]{12}\\}\\Z"
options:NSRegularExpressionAnchorsMatchLines
error:&error];
// use the regex to match the string ...
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