闪烁隐藏并使用块 [英] Blink hidden and using blocks

问题描述

我有方法:

- (void)blinkView:(UIView *)view
{
    view.layer.opacity = 0.0f;
    view.hidden = NO;

    [UIView beginAnimations:@"Blinking" context:nil];
    [UIView setAnimationRepeatCount:1.0];
    [UIView setAnimationDuration:0.6f];
    [UIView setAnimationCurve:UIViewAnimationCurveEaseInOut];
    view.layer.opacity = 1.0f;
    [UIView commitAnimations];
}

我该如何用块编写此代码，以及如何必须实现具有反作用的方法(用眨眼隐藏uiview)?

How can i write this code with blocks, and how i must implement method with reverse effect (hide uiview with blink) ?

推荐答案

[UIView transitionWithView: view
       duration:0.6f
       options:UIViewAnimationOptionCurveEaseInOut
       animations:^{ view.layer.opacity = 1.0f; }
       completion:NULL];

或

[UIView transitionWithView: view
       duration:0.6f
       options:UIViewAnimationOptionCurveEaseInOut | UIViewAnimationOptionRepeat | UIViewAnimationOptionAutoreverse
       animations:^{ view.layer.opacity = 1.0f; }
       completion:NULL];

您可以通过递归调用动画块来设置重复计数(请参见此处).

You can set the repeat count by recursively calling the animation block (see here).

希望它会对您有所帮助.

Hope it will help you.

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