如何使UIBlockButton适合ARC? [英] How to make UIBlockButton suit with ARC?

问题描述

我正在使用这篇文章中的UIBlockButton代码:

typedef void (^ActionBlock)();

@interface UIBlockButton : UIButton {
  ActionBlock _actionBlock;
}

-(void) handleControlEvent:(UIControlEvents)event 
                 withBlock:(ActionBlock) action;

@implementation UIBlockButton

-(void) handleControlEvent:(UIControlEvents)event 
                 withBlock:(ActionBlock) action
{
  _actionBlock = Block_copy(action);
  [self addTarget:self action:@selector(callActionBlock:) forControlEvents:event];
}

-(void) callActionBlock:(id)sender{
  _actionBlock();
}

-(void) dealloc{
  Block_release(_actionBlock);
  [super dealloc];
}
@end

但是我将代码更改为ARC，如何更改代码以确保一切正常?

but I changed my code to under ARC, how to change the code to make sure everything works well?

推荐答案

标题:

@interface UIBlockButton : UIButton

- (void) handleControlEvent: (UIControlEvents) event withBlock: (dispatch_block_t) action;

@end

实施:

@interface UIBlockButton ()
@property(copy) dispatch_block_t actionBlock;
@end

@implementation UIBlockButton
@synthesize actionBlock;

- (void) handleControlEvent: (UIControlEvents) event withBlock: (dispatch_block_t) action
{
    [self setActionBlock:action];
    [self addTarget:self action:@selector(callActionBlock:) forControlEvents:event];
}

- (void) callActionBlock: (id) sender
{
    if (actionBlock) actionBlock();
}

@end

但是请注意，多次调用handleControlEvent:withBlock:会覆盖您的代码块，使用此实现，您不能对不同的事件采取不同的操作.另外，您可能应该为该类使用不同的前缀而不是UI，以防止与Apple代码的潜在冲突.

But note that multiple calls to handleControlEvent:withBlock: will overwrite your block, you can’t have different actions for different events with this implementation. Also, you should probably use a different prefix for the class instead of UI to prevent potential clashes with Apple’s code.

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