有没有办法禁止从类的实例向类添加属性? [英] Is there a way to disable adding properties into a class from an instance of the class?

问题描述

是否可以禁用将属性添加到来自该类实例的类.

Is there a way to disable adding properties into a class from an instance of the class.

我的意思是:

考虑此类:

class a {
 private $v1;
 public $v2;

 function func(){
 ...
 }
}

如果我这样做:

$ins = new a;
$ins->temp = "A variable created from outside the class! C*ap!";
var_dump($ins);

输出:

object(a)#1 (3) {
  ["v1":"a":private]=>
  NULL
  ["v2"]=>
  NULL
  ["temp"]=>
  string(48) "A variable created from outside the class! C*ap!"
}

Can this be disabled? `

推荐答案

也许您可以实现

Perhaps you can implement __set() and throw an exception from there:

class a {
    private $v1;
    public $v2;

    public function __set($name, $value) {
        throw new Exception("Cannot add new property \$$name to instance of " . __CLASS__);
    }
}

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