获取家长班级名称? [英] Get parent class name?

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本文介绍了获取家长班级名称?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

class A(object):
    def get_class(self):
        return self.__class__

class B(A):
    def __init__(self):
        A.__init__(self)

b = B()
print b.get_class()

此代码将显示<class '__main__.B'>.

如何获取已在其中定义方法的类名(即A)?

How can I get the class name where the method has been defined (namely A)?

推荐答案

来自文档: Class对象具有__name__属性.通过派生类的__bases__ attr对基类进行内省(例如,如果代码位于派生类中),可能会更干净.

Class objects have a __name__ attribute. It might cleaner to introspect the base class(es) through the __bases__ attr of the derived class (if the code is to live in the derived class for example).

>>> class Base(object):
...     pass
...
>>> class Derived(Base):
...     def print_base(self):
...         for base in self.__class__.__bases__:
...             print base.__name__
...
>>> foo = Derived()
>>> foo.print_base()
Base

这篇关于获取家长班级名称?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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