在PHP中获取子类的名称 [英] Getting the name of a child class in PHP

问题描述

让我们说我正在建立一个基础类，该类将由儿童类扩展.因此，基类称为Base，子类可以为Child1，Child2等.

Lets say I'm building a base class which will be extended upon by the children class. So a base class is called Base and children can be Child1, Child2, etc.

在基类的构造函数中，如何获取Child1/Child2的值?

In the base class's constructor, how can i get the value of Child1/Child2?

这都是使用PHP

推荐答案

基类实际上绝对不应依赖于子类的信息---

A base class should really never depend on information about child classes---

回答您的问题:

class base {
    public function __construct() {
        print "Class:" . get_class($this) . "\n";
    }
}

class child extends base{
    public function __construct() {
        parent::__construct();
    }
}
$c = new child();

仅供以后参考-可以使用get_Called_class()在静态上下文中实现，但这仅在PHP> = 5.3中可用

Just for future reference -- this can be acheived in a static context using get_called_class(), but this is only available in PHP >= 5.3

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