如何在PHP中调用super? [英] How to call super in PHP?

问题描述

我有一个classB扩展了classA.在classB中，我定义了方法fooBar()，该方法也在classA中定义.在classB的fooBar()中，我想一开始就调用classA的fooBar().从Objective-C开始，这就是我惯用的方式.这在PHP中可行吗?如果可以，怎么办?

I have a classB which extends classA. In classB I define a method fooBar() which is also defined in classA. In fooBar() of classB I want to call fooBar() of classA at the beginning. Just the way I'm used to, from Objective-C. Is that possible in PHP? And if so, how?

推荐答案

parent::fooBar();

直接从手册中:

...双冒号是允许访问...覆盖的类的属性或方法的令牌.

The ... double colon, is a token that allows access to ... overridden properties or methods of a class.

...

<?php
class MyClass
{
    protected function myFunc() {
        echo "MyClass::myFunc()\n";
    }
}

class OtherClass extends MyClass
{
    // Override parent's definition
    public function myFunc()
    {
        // But still call the parent function
        parent::myFunc();
        echo "OtherClass::myFunc()\n";
    }
}

$class = new OtherClass();
$class->myFunc();
?>

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