PHP对象实例可以知道其名称吗? [英] Can a PHP object instance know its name?

问题描述

如果我有这样的代码:

class Person {
    $age;
    $height;
    $more_stuff_about_the_person;

    function about() {
        return /* Can I get the person's name? */;
    }
}

$John = new Person();
$Peter = new Person();

print $John->about();  // Print "John".
print $Peter->about(); // Print "Peter".

是否可以从方法中打印存储为变量名的人员姓名?

Is it possible to print the person's name, stored as the variable name, from the method?

由于它不是标准程序，所以我认为这是个坏主意.

As it's not standard procedure, I'm guessing it's a bad idea.

我查了一下，找不到任何东西.

I've looked it up and I can't find anything about it.

推荐答案

否.对象可以有多个名称，也可以没有名称.这里会发生什么:

No. Objects can have multiple names, or no names. What would happen here:

$John = new Person();
$Richie = $John;      // $John and $Richie now both refer to the same object.
print $Richie->about();

或此处:

function f($person)
{
    print $person->about();
}

f(new Person());

如果对象需要知道自己的名称，则需要将其名称显式存储为成员变量(如$age和$height).

If the objects need to know their own names, then they need to explicitly store their names as member variables (like $age and $height).

这篇关于PHP对象实例可以知道其名称吗?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！