获取实例的静态属性 [英] Get a static property of an instance

问题描述

如果我在PHP中有一个实例，那么获取该实例的静态属性(类变量")的最简单方法是什么?

If I have an instance in PHP, what's the easiest way to get to a static property ('class variable') of that instance ?

此

$classvars=get_class_vars(get_class($thing));
$property=$classvars['property'];

声音真的过大了.我希望

Sound really overdone. I would expect

$thing::property

或

$thing->property

这是一个老问题.有更明显的方法可以在较新的版本中执行此操作 PHP，请在下面搜索.

this is an old question. There are more obvious ways to do this in newer PHP, search below.

推荐答案

您需要先查找类名:

$class = get_class($thing);
$class::$property

$ property当然必须定义为static和public.

$property must be defined as static and public of course.

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