使用正则表达式的vqmod通配符搜索 [英] vqmod wildcard search using regex

问题描述

作为一个示例，我试图替换所有的$this->load->model(*);，*表示通配符搜索/替换.在正则表达式中执行此操作的正确方法是什么?

As an example here I am trying to replace all $this->load->model(*);, the * represents a wildcard search/replace. What is the correct way to do this in a regex?

<operation>
    <search regex="true" position="replace"><![CDATA[ $this->load->model(.*); ]]></search>
    <add><![CDATA[ $this->load->model('catalog/information'); ]]></add>
</operation>

推荐答案

所需的转义应该很小.您只需要像这样转义$和括号

The escaping required should be pretty minimal. You only need to escape the $ and the parentheses like so

<search regex="true" position="replace"><![CDATA[~\$this->load->model\(.*?\);~]]></search>

同样，您已经正确地回答了这个问题，您需要添加一个定界符(我发现~出现在字符串中的可能性远小于/，因此使用了它)

Also as you've rightly done in your answer to this, you need to add a delimiter (I find ~ is far less likely to be in a string than / hence using that instead)

这篇关于使用正则表达式的vqmod通配符搜索的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！