OpenCV cv2.fillPoly与cv2.fillConvexPoly:多边形顶点数组的预期数据类型? [英] OpenCV cv2.fillPoly vs. cv2.fillConvexPoly: expected data type for array of polygon vertices?

问题描述

我有以下代码:

import cv2
import numpy

ar = numpy.zeros((10,10))
triangle = numpy.array([ [1,3], [4,8], [1,9] ], numpy.int32)

如果我像这样使用cv2.fillConvexPoly:

If I use cv2.fillConvexPoly like so:

cv2.fillConvexPoly(ar, triangle, 1)

则结果如预期.但是，如果我尝试:

then the results are as expected. If, however, I try:

cv2.fillPoly(ar, triangle, 1)

然后我得到一个失败的断言.这似乎与断言相同，如果我对不具有dtype numpy.int32的cv2.fillConvexPoly使用numpy数组，则该断言将失败. cv2.fillPoly和cv2.fillConvexPoly的第二个参数期望不同的数据类型吗?如果是这样，我应该为cv2.fillPoly使用什么?

then I get a failed assertion. This seems to be identical to the assertion that fails if I use a numpy array for cv2.fillConvexPoly that does not have dtype numpy.int32. Do cv2.fillPoly and cv2.fillConvexPoly expect different data types for their second argument? If so, what should I be using for cv2.fillPoly?

推荐答案

cv2.fillPoly和cv2.fillConvexPoly为它们的点数组使用不同的数据类型，因为fillConvexPoly仅绘制一个多边形，而fillPoly绘制一个(python)他们的名单.因此，

cv2.fillPoly and cv2.fillConvexPoly use different data types for their point arrays, because fillConvexPoly draws only one polygon and fillPoly draws a (python) list of them. Thus,

cv2.fillConvexPoly(ar, triangle, 1)
cv2.fillPoly(ar, [triangle], 1)

是调用这两种方法的正确方法.如果您有square和hexagon点数组，则可以使用

are the correct ways to call these two methods. If you had square and hexagon point arrays, you could use

cv2.fillPoly(ar, [triangle, square, hexagon], 1)

绘制所有三个.

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