使用python的opencv-将roi复制到新的较小图像 [英] opencv using python - copy roi to new smaller image

问题描述

在使用Python的opencv中- 如何创建一个新图像，该图像只是其他图像的roi副本? 肯定有一些与

In opencv using python - How can I create a new image that is simply a copy of an roi from another image? Surely there is something along the lines of

Mat roi = img( Rect(x,y,w,h) );

用于python或比蛮力更优雅的任何东西

for python, or anything more elegant than the brute force

rect=[x,y,w,h]
img = cv2.imread(subst)
roi= np.zeros((rect[3],rect[2],3),np.uint8)  #is this really reversed? who ordered that?
cv2.rectangle(img,(x,y),(w+x,h+y),[255,0,0],thickness=1)
cv2.imshow('img',img)
cv2.waitKey()
#cv.Copy(cv.fromarray(img),cv.fromarray(roi),cv.fromarray(mask))  #can't make it work...
for x in range(rect[2]):
    for y in range(rect[3]):
        roi[y,x,:]=img[y+rect[1],x+rect[0],:]

和顺便说一句，x，y坐标如何排序-[x，y，c]或[y，x，c]在x(水平)和y(垂直)处指定点?看来它的[y，x，c]是iiuc，而cv2.rectangle是(x，y)而img.shape是(y，x)，它甚至比(g，r，b)还要烦人的(r，g，b)....

and btw how do the x,y coordinates order - is it [x,y,c] or [y,x,c] to specify a point at x (horizontal) and y (vertical)? It seems like its [y,x,c], iiuc, while the cv2.rectangle is (x,y) and img.shape is (y,x) which would be even more annoying than (g,r,b) instead of (r,g,b)....

推荐答案

import os
import cv2

img = cv2.imread(filename)
roi = img[row:row+height,column:column+width]
cv2.imshow('ROI',roi)
cv2.waitKey(0)

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