圆检测不重叠 [英] Circle detection without overlapping

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本文介绍了圆检测不重叠的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想在以下条件下进行圆检测:重叠的圆将被计为1个圆.

I want to do circle detection under the condition that: overlap circles will be count as 1 circle.

特别是,当我进行圆检测并将下面的图像的每个圆(实际上是花粉或类似圆的物体)上加上字母"P"时

Particularly, when I do circle detection and put the letter "P" to every circle (actually they are pollen, or circle-like objects) for the image below

它变成了

(同一张照片,但我不知道为什么在这里上传时它变成水平的)

(The same photo but I don't know why it turned to horizontal when I uploaded it here)

但是我只希望每个圆圈1个字母P.调整半径也许是个好主意,但是我还有很多其他照片要去,所以我希望有一种方法可以忽略重叠.

But I just want 1 letter P for each circle. Adjusting the radius maybe a good idea, but I still have lot of other photos to go, so I hope there is a method to ignore overlapping.

这是我的代码:

import cv2
import numpy as np


path = "./sample.JPG"
font = cv2.FONT_HERSHEY_COMPLEX



def image_resize(image, width = None, height = None, inter = cv2.INTER_AREA):
    # initialize the dimensions of the image to be resized and
    # grab the image size
    dim = None
    (h, w) = image.shape[:2]

    # if both the width and height are None, then return the
    # original image
    if width is None and height is None:
        return image

    # check to see if the width is None
    if width is None:
        # calculate the ratio of the height and construct the
        # dimensions
        r = height / float(h)
        dim = (int(w * r), height)

    # otherwise, the height is None
    else:
        # calculate the ratio of the width and construct the
        # dimensions
        r = width / float(w)
        dim = (width, int(h * r))

    # resize the image
    resized = cv2.resize(image, dim, interpolation = inter)

    # return the resized image
    return resized


# In[22]:

iml = cv2.imread(path,cv2.IMREAD_COLOR)
img = image_resize(iml,width=960)


cimg = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
cimg = cv2.medianBlur(cimg,5)

#Circle detection to detect pollen in big images, return the center's coordinates and radius of circles in array
circles = cv2.HoughCircles(cimg,cv2.HOUGH_GRADIENT,1,10,param1=15,param2=20,minRadius=10,maxRadius=25)
circles = np.uint16(np.around(circles))[0,:]


for i in circles:
     cv2.putText(img,'P',(i[0],i[1]), font, 0.5,(0,0,255),1,cv2.LINE_AA)

cv2.imwrite("./output.jpg",img)

推荐答案

我建议改用轮廓.但是,如果您确实想使用HoughCircles,请查看函数中的第4个参数.改变这一点,我可以摆脱重叠.此外,我在HoughCircles函数中对canny threshold的参数进行了一些调整,直到获得所需的结果.我建议您在得出结论之前先了解一下参数.

I would suggest using contours instead. However, if you do want to use HoughCircles, look at the 4th parameter in the function. Changing this, I could get rid of the overlappings. Additionally, I tweaked a bit the parameters for canny threshold in the HoughCircles function until I got the desired results. I'd suggest understanding the parameters well before coming up with a conclusion.

代码:

import cv2
import numpy as np

arr = cv2.imread("U:/SO/032OR.jpg")
print(arr.shape)
imggray = cv2.cvtColor(arr, cv2.COLOR_BGR2GRAY)
# Not median blur 
imggray = cv2.GaussianBlur(imggray, (9,9),3)

circles_norm = cv2.HoughCircles(imggray, cv2.HOUGH_GRADIENT, 1, imggray.shape[0]/16, 
                                param1=20, param2=8, minRadius=15, maxRadius=30)
circles_norm = np.uint16(np.around(circles_norm))[0,:]

for i in circles_norm:
    center = (i[0], i[1])
    cv2.putText(arr, 'P', (i[0], i[1]), cv2.FONT_HERSHEY_COMPLEX, 0.5, 
               (0,0,255),1,cv2.LINE_AA)

结果:

这篇关于圆检测不重叠的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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