使用gcov是否可以覆盖共享库的代码? [英] Is it possible code coverage of a shared library using gcov?
问题描述
我尝试测试使用OpenCV共享库的可执行文件.当使用gcov知道覆盖了哪些代码行时,我仅获得有关库的.cpp文件和.hpp的信息.没有显示有关该库的.cpp文件的信息.
I try to test an executable which uses OpenCV shared library. When using gcov to know what code lines were covered I only get info about my .cpp files and .hpp of the library. No info is shown about .cpp files of the library.
我编译并与-pg --coverage标志链接.
I compiled and linked with -pg --coverage flags.
推荐答案
是的,gcov可以提供有关共享库的覆盖率信息.如果我正确地记住了使它在项目中起作用的问题,则可能是在动态库的链接上未包含--coverage
标志.这是我可以创建的最小示例.
Yes, gcov can give coverage information about a shared library. If I remember correctly from the problems I had getting this to work on my project, you're probably not including the --coverage
flag on the linking of the dynamic library. Here's the smallest example I could create.
Makefile:
CXXFLAGS += --coverage
LDFLAGS += --coverage
myexec: myexec.cpp libmylib.so
libmylib.so: mylib.o
gcc --coverage -shared -Wl,-soname,libmylib.so -o libmylib.so mylib.o
mylib.o: CXXFLAGS += -fPIC
myexec.cpp:
myexec.cpp:
#include "mylib.h"
int main(int argc, char** argv)
{
return is_even(argc);
}
mylib.h
#ifndef MYLIB_H
#define MYLIB_H
int is_even(int num);
#endif
mylib.cpp
mylib.cpp
#include "mylib.h"
int is_even(int num)
{
if (num % 2)
return false;
else
return true;
}
make的输出(因此您可以确切地看到构建是什么):
Output of make (so you can see exactly what the build was):
g++ --coverage -fPIC -c -o mylib.o mylib.cpp
gcc --coverage -shared -Wl,-soname,libmylib.so -o libmylib.so mylib.o
g++ --coverage --coverage myexec.cpp libmylib.so -o myexec
我使用LD_LIBRARY_PATH="." ./myexec a
运行可执行文件,然后运行gcov mylib.cpp
.这是mylib.cpp.gcov的内容:
I ran the executable using LD_LIBRARY_PATH="." ./myexec a
, and then ran gcov mylib.cpp
. Here's the contents of mylib.cpp.gcov:
-: 0:Source:mylib.cpp
-: 0:Graph:mylib.gcno
-: 0:Data:mylib.gcda
-: 0:Runs:1
-: 0:Programs:1
-: 1:#include "mylib.h"
-: 2:
1: 3:int is_even(int num)
-: 4:{
1: 5: if (num % 2)
#####: 6: return false;
-: 7: else
1: 8: return true;
-: 9:}
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