cv :: Mat的向量在它们之间链接 [英] Vector of cv::Mat are linked between them

问题描述

std::vector<cv::Mat1f> mat = std::vector<cv::Mat1f>(10,cv::Mat1f::zeros(1,10));
mat[0]+=1;
for(size_t i=0;i<mat.size();i++)
    std::cout<<mat[i]<<std::endl;

它会打印:

[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]

如何避免这种情况?向量初始化必须是内联的.

How can I avoid this? It would be very important that the vector initialization is inline.

推荐答案

您不能这样做. vector构造函数使用Mat复制构造函数，该复制构造函数仅复制标头，而不复制数据.您需要以某种方式显式使用clone()，或每次都创建一个新矩阵:例如:

You can't do that. The vector constructor uses the Mat copy constructor, which only copies the header but not the data. You need to explicitly use clone() somehow, or create a new matrix every time: E.g:

std::vector<cv::Mat1f> mat(10);
for (size_t i = 0; i < mat.size(); i++) {
    mat[i] = cv::Mat1f(1, 10, 0.f);
}

或:

cv::Mat1f m = cv::Mat1f(1, 10, 0.f);
std::vector<cv::Mat1f> mat(10);
for (size_t i = 0; i < mat.size(); i++) {
    mat[i] = m.clone();
}

或:

std::vector<cv::Mat1f> mat(10);
std::generate(mat.begin(), mat.end(), []() {return cv::Mat1f(1, 10, 0.f); });

或:

cv::Mat1f m = cv::Mat1f(1, 10, 0.f);
std::vector<cv::Mat1f> mat(10);
std::generate(mat.begin(), mat.end(), [&m]() {return m.clone(); });

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