openlayers3所选功能的样式是否相同(只有一个更改的属性)? [英] openlayers3 same style for selected features (only one changed property)?

问题描述

我有一个带有样式定义的ol3层.我想对选择交互使用相同的样式:

I have an ol3 layer with a style definition. I would like to use the same style for the select interaction:

style = function(feature, resolution) {

    var iconFont = 'FontAwesome';
    var iconFontText = '\uf1f8'; // fa-trash
    var iconSize = 24;
    var col = 'black';

    var styles = [];

    var styleIcon = new ol.style.Style({
        text: new ol.style.Text({
            font: 'Normal ' + iconSize + 'px ' + iconFont,
            text: iconFontText,
            fill: new ol.style.Fill({color: col})
        })
    });
    styles.push(styleIcon);

    }

    return styles;
};

    new ol.layer.Vector({
            source: that.source,
            style: style
        });

    new ol.interaction.Select({
                features: that.selectedFeatures,
                style: style
            })

我只想更改样式的一个属性(iconSize)以突出显示所选功能.有可能吗?我不想定义两个单独的样式，但是如果可以的话，可以以编程方式复制样式并替换iconsize值.

I only want to change one property (iconSize) of the style to highlight the selected features. Is that somehow possible? I do not want to define two seperate styles, but I would be ok if it was somwhow possible to programmatically copy the style and replace the iconsize value.

推荐答案

现在我找到了可行的解决方案:

Now I found a working solution:

您可以在样式函数中添加一个附加参数(例如，突出显示[bool]):

You can add an additional argument (e.g. highlight [bool]) to the style function:

style = function(feature, resolution, highlight) {
...
}

，而不是

new ol.interaction.Select({
                features: that.selectedFeatures,
                style: style
            })

您可以使用

new ol.interaction.Select({
                features: that.selectedFeatures,
                style: function(feature,resolution){
                     return style(feature,resolution,true);
                }
            })

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