openpyxl按名称获取工作表 [英] openpyxl get sheet by name
本文介绍了openpyxl按名称获取工作表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在将一些数据写入Excel文件,但是我不知道如何调整代码以便能够控制我要写入的工作表:
I am writing some data into an Excel file, but I dont know how to adjust the code in order to be able to control which sheet I am writing into:
wb = load_workbook(filename)
active_ws = wb.active
代替wb.active
,我怎么能说类似Sheets('Data')
的东西(这就是VBA语法的样子……)?
Instead of wb.active
, how can I say something like Sheets('Data')
(this is how the VBA syntax would look like...)?
推荐答案
您应使用wb[sheetname]
from openpyxl import load_workbook
wb2 = load_workbook('test.xlsx')
ws4 = wb2["New Title"]
PS:
您应该检查工作表名称是否为wb.sheetnames
PS:
You should check if your sheet in sheet names wb.sheetnames
print(wb2.sheetnames)
['Sheet2', 'New Title', 'Sheet1']
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