使用“共享"选项编译OpenSSL吗? [英] Compile OpenSSL with the 'shared' option?

问题描述

在CentOS 5.4上，OpenSSL可以正常编译，而无需使用共享"选项.但是当我通过该选项时，编译失败并显示为:

On CentOS 5.4, OpenSSL compiles fine without 'shared' option. But when I passed that option the compilation fails with:

/usr/bin/ld:libcrypto.a(x86_64-gcc.o):在创建共享库时不能使用针对本地符号"的重定位R_X86_64_32；用-fPIC重新编译

/usr/bin/ld: libcrypto.a(x86_64-gcc.o): relocation R_X86_64_32 against `a local symbol' can not be used when making a shared object; recompile with -fPIC

当我尝试:./config shared CFLAGS=-fPIC时不起作用.

When I try: ./config shared CFLAGS=-fPIC that doesn't work.

如何使OpenSSL使用共享"选项进行编译?

What can I do to get OpenSSL to compile with the 'shared' option?

谢谢

推荐答案

这里存在同样的问题，但通常Makefile将考虑环境变量作为编译器或链接器选项.

Same problem here, BUT usually Makefiles will consider environment variables for compiler or linker options.

因此，如果在调用configure脚本之前将-fPIC选项 放置，则应注意这一点.您可以执行以下操作:

So, if you place the -fPIC option before calling the configure script, it should take care of it. You can do it with:

CFLAGS=-fPIC ./config shared --prefix=/your/path

或

export CFLAGS=-fPIC
./config shared --prefix=/your/path

对我有用.

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