Python:os.path.isfile无法识别以数字开头的文件 [英] Python: os.path.isfile won't recognise files beginning with a number
问题描述
因此,我正在尝试将os.path.isfile
或os.path.exists
合并到我的代码中,从而在搜索以字母开头的文件名时成功找到某些常规文件(pdf,png).
So, I'm trying to incorporate os.path.isfile
or os.path.exists
into my code with success in finding certain regular files(pdf,png) when searching for filenames that begin with a letter.
我正在使用的文件命名标准(由于用户而不能更改)以数字开头,随后无法使用相同的方法找到.有什么方法可以使这些文件可以被.isfile
或.exists
发现?
The file naming standard that I'm using (and can't change due to the user) starts with a number and subsequently can't be found using the same method. Is there a way that I can make these files discoverable by .isfile
or .exists
?
我要搜索的文件是.txt文件.
The files I'm searching for are .txt files.
os.path.isfile("D:\Users\spx9gs\Project Work\Data\21022013AA.txt")
os.path.isfile("D:\Users\spx9gs\Project Work\Data\AA21022013.txt")
返回:
错误
是
推荐答案
您需要使用原始字符串,或转义反斜杠.在文件名中:
You need to use raw strings, or escape your backslashes. In the filename:
"D:\Users\spx9gs\Project Work\Data\21022013AA.txt"
\210
将被解释为八进制转义码,因此您将无法获得正确的文件名.
the \210
will be interpreted as an octal escape code so you won't get the correct filename.
这两种方法都可以使用:
Either of these will work:
r"D:\Users\spx9gs\Project Work\Data\21022013AA.txt"
"D:\\Users\\spx9gs\\Project Work\\Data\\21022013AA.txt"
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