如何使用Python在Windows中创建符号链接? [英] How to create symlinks in windows using Python?

问题描述

我试图在Windows 8上使用Python创建symlinks.我发现了这篇文章和这是我脚本的一部分.

I am trying to create symlinks using Python on Windows 8. I found This Post and this is part of my script.

import os

link_dst = unicode(os.path.join(style_path, album_path))
link_src = unicode(album_path)
kdll = ctypes.windll.LoadLibrary("kernel32.dll")
kdll.CreateSymbolicLinkW(link_dst, link_src, 1)

首先，它只有在通过管理员cmd执行后才能创建符号链接.为什么会这样?

Firstly, It can create symlinks only when it is executed through administrator cmd. Why is that happening?

第二，当我尝试从Windows资源管理器中打开这些符号链接时，出现此错误:

Secondly, When I am trying to open those symlinks from windows explorer I get This Error:

...Directory is not accessible. The Name Of The File Cannot Be Resolved By The System.

是否有使用Python创建符号链接的更好方法?如果没有，我该如何解决?

编辑

这是album_linker中的for循环:

This is the for loop in album_linker:

def album_Linker(album_path, album_Genre, album_Style):
genre_basedir = "E:\Music\#02.Genre"
artist_basedir = "E:\Music\#03.Artist"
release_data_basedir = "E:\Music\#04.ReleaseDate"
for genre in os.listdir(genre_basedir):
    genre_path = os.path.join(genre_basedir, "_" + album_Genre)
    if not os.path.isdir(genre_path):
        os.mkdir(genre_path)
    album_Style_list = album_Style.split(', ')
    print album_Style_list
    for style in album_Style_list:
        style_path = os.path.join(genre_path, "_" + style)
        if not os.path.isdir(style_path):
            os.mkdir(style_path)
        album_path_list = album_path.split("_")
        print album_path_list
        #link_dst = unicode(os.path.join(style_path, album_path_list[2] + "_" + album_path_list[1] + "_" + album_path_list[0]))
        link_dst = unicode(os.path.join(style_path, album_path))
        link_src = unicode(album_path)
        kdll = ctypes.windll.LoadLibrary("kernel32.dll")
        kdll.CreateSymbolicLinkW(link_dst, link_src, 1)

使用album_Genre和album_Style，然后在E:\Music\#02.Genre下创建目录.它还从脚本主体中获取album_path.这个album_path是我要在E:\Music\#02.Genre\Genre\Style下创建符号链接的目录路径.因此，album_path是从脚本主体中的另一个for循环获取的变量

It takes album_Genre and album_Style And then It creates directories under E:\Music\#02.Genre . It also takes album_path from the main body of the script. This album_path is the path of directory which i want to create the symlink under E:\Music\#02.Genre\Genre\Style . So album_path is a variable taken from another for loop in the main body of the script

for label in os.listdir(basedir):
label_path = os.path.join(basedir, label)
for album in os.listdir(label_path):
    album_path = os.path.join(label_path, album)
    if not os.path.isdir(album_path):
        # Not A Directory
        continue
    else:
        # Is A Directory
        os.mkdir(os.path.join(album_path + ".copy"))
        # Let Us Count
        j = 1
        z = 0
        # Change Directory
        os.chdir(album_path)

推荐答案

首先，它只有在通过管理员cmd执行后才能创建符号链接.

用户需要创建符号链接"权限才能创建符号链接.默认情况下，普通用户没有，但管理员有.一种更改方法是使用安全策略编辑器.以管理员身份打开命令提示符，运行secpol.msc，然后转到Security Settings\Local Policies\User Rights Assignment\Create symbolic links进行更改.

Users need "Create symbolic links" rights to create a symlink. By default, normal users don't have it but administrator does. One way to change that is with the security policy editor. Open a command prompt as administrator, run secpol.msc and then go to Security Settings\Local Policies\User Rights Assignment\Create symbolic links to make the change.

第二，当我尝试从Windows资源管理器中打开这些符号链接时，出现此错误:

您没有在文件名中转义反斜杠.只需在原始字符串的前面添加"r"，文件名便会更改.您正在设置一个不存在的文件名，因此资源管理器找不到它.

You aren't escaping the backslashes in the file name. Just by adding an "r" to the front for a raw string, the file name changes. You are setting a non-existant file name and so explorer can't find it.

>>> link_dst1 = "E:\Music\#02.Genre_Electronic_Bass Music\1-800Dinosaur-1-800-001_[JamesBlake-Voyeur(Dub)AndHolyGhost]_2013-05-00"
>>> link_dst2 = r"E:\Music\#02.Genre_Electronic_Bass Music\1-800Dinosaur-1-800-001_[JamesBlake-Voyeur(Dub)AndHolyGhost]_2013-05-00"
>>> link_dst1 == link_dst2
False
>>> print link_dst1
E:\Music\#02.Genre_Electronic_Bass Music☺-800Dinosaur-1-800-001_[JamesBlake-Voyeur(Dub)AndHolyGhost]_2013-05-00

这篇关于如何使用Python在Windows中创建符号链接?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！