进程结束后如何自动关闭`qemu`的执行? [英] How to automatically close the execution of the `qemu` after end of process?

问题描述

我希望打开并显示输出后的qemu窗口在运行pintOS

I want that the qemu window after opening and showing the output automatically closes after running pintOS

就像我在tcsh shell中运行命令pintos -- run alarm-multiple一样，qemu显示进程开始，然后一些alarm-notifications然后进程结束，但是之后，qemu窗口将不会关闭

Like when i run the command pintos -- run alarm-multiple in tcsh shell, qemu displays that process begins ,then some alarm-notifications and then the process ends, but after that the qemu window won't close

我想在成功完成系统调用后退出窗口.

I want to exit the window after successful completion of my system call.

推荐答案

已更新:

新解决方案

这是另一个对 pintos run ... 和 make grade

Here is another better solution that will work for both pintos run ... and make grade

将此行添加到循环之前的 devices/shutdown.c :: :: shutdown_power_off(void).

add this line to devices/shutdown.c :: shutdown_power_off(void) before the loop.

outw( 0x604, 0x0 | 0x2000 ); 

---

旧解决方案

对于较新版本的qemu，您需要使用选项运行它

For the newer versions of qemu you need to run it with the option

-device isa-debug-exit

任何对IO端口的写操作都会退出，默认情况下为0x501

Which exits on any write to an IO port, by default it's 0x501

ie ，您需要在 pintos 中添加一行 run_qemu 子例程

i.e in your pintos project under the src/utils directory you will need to add one line to the pintos file in the run_qemu subroutine

sub run_qemu {
    print "warning: qemu doesn't support --terminal\n"
       if $vga eq 'terminal';
    print "warning: qemu doesn't support jitter\n"
       if defined $jitter;
    my (@cmd) = ('qemu-system-i386');

    push (@cmd, '-device', 'isa-debug-exit'); # <====== add this line
    ..
    ..
    push (@cmd, '-monitor', 'null') if $vga eq 'none' && $debug eq 'none';
    run_command (@cmd);
}

和 devices 目录下的 shutdown.c 文件中 在for循环后的 shutdown_power_off 函数中添加此行

and in shutdown.c file under the devices directory add this line in the shutdown_power_off function after the for loop

for (p = s; *p != '\0'; p++)
    outb (0x8900, *p);

outb (0x501, 0x31); // <====== add this line

Qemu的退出代码是值的两倍加一，因此无法干净地退出.使用0x31，这将导致qemu退出代码为0x63

Qemu's exit code is double the value plus one, so there is no way to exit cleanly. Use 0x31 which should result in a qemu exit code of 0x63

最终使用-q选项运行pintos

finally run pintos with -q option

pintos -q run alarm-multiple

• 注意:此解决方案不适用于 make grade ，请参阅以下@ pranav3688的注释以获取解决方案.

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