系统时间是10位,如何? [英] System Time is 10 Digit , How?
问题描述
我对当前系统时间有疑问.我有基于命令行的软件. 当我运行该软件时,它向我显示了执行开始和结束的时间.即
I have question about the current system time. I have software based on command line. When I run that software, it shows me the time at both the start and end of execution. ie
- 开始:
The current system time is: 1378258559
- 结尾:
The current system time is : 1378258570
- Start:
The current system time is: 1378258559
- End:
The current system time is : 1378258570
我不知道时间是秒还是分钟. 1378258559
是如何计算的?两个数字之间的区别是11
.
I do not know if the time is in seconds or minutes. How is the 1378258559
is calculated? The difference between the two numbers is 11
.
仅供参考,我系统上的当前日期和时间是:04/09/2013 9:50 AM
FYI, the current date and time on my system is: 04/09/2013 9:50 AM
推荐答案
此网站有一个计算器:
这是自格林尼治标准时间1970年1月1日以来的秒数.
It is the number of seconds since January 1st, 1970 at midnight GMT.
11,是因为某事花了11秒.
The 11, is because something took 11 seconds.
这是一篇说明为什么选择1970以及其定义的帖子:
Here's a post explaining why 1970 was chosen along with the definition:
- Unix时间(或POSIX时间)是一种用于描述时间点的系统,时间点定义为自1970年1月1日午夜多点协调世界时(UTC)起经过的秒数.
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