PHP Null合并运算符混乱 [英] PHP Null coalescing operator confusion

问题描述

我有点困惑. PHP文档说:

// Example usage for: Null Coalesce Operator
$action = $_POST['action'] ?? 'default';

// The above is identical to this if/else statement
if (isset($_POST['action'])) {
    $action = $_POST['action'];
} else {
    $action = 'default';
}

但是我自己的示例说的却大不相同:

But my own example says something very different:

echo "<pre>";
$array['intValue'] = time();
$array['stringValue'] = 'Hello world!';
$array['boolValue'] = false;


$resultInt = isset($array['intValue']) ?? -1;
$resultString = isset($array['stringValue']) ?? 'Another text';
$resultBool = isset($array['boolValue']) ?? true;

var_dump($resultInt);
var_dump($resultString);
var_dump($resultBool);

echo '<br/>';

if(isset($array['intValue'])) $_resultInt = $array['intValue'];
else $_resultInt = -1;

if(isset($array['stringValue'])) $_resultString = $array['stringValue'];
else $_resultString = 'Another text';

if(isset($array['boolValue'])) $_resultBool = $array['boolValue'];
else $_resultBool = true;


var_dump($_resultInt);
var_dump($_resultString);
var_dump($_resultBool);

echo "</pre>";

我的输出:

bool(true)
bool(true)
bool(true)

int(1534272962)
string(12) "Hello world!"
bool(false)

因此，如我的示例所示，if条件与文档中所说的空合并运算符的结果不同.有人可以解释我，我做错了什么吗?

So, as my example shows, the if-condition does not result in the same as the null coalescing operator does as the documentation says. Can somebody explain me, what I did wrong?

谢谢！

推荐答案

您正在做的事情:

$resultInt = isset($array['intValue']) ?? -1;
$resultString = isset($array['stringValue']) ?? 'Another text';
$resultBool = isset($array['boolValue']) ?? true;

但是??的要点是它为您执行了isset调用.因此，请尝试使用此方法，而无需使用isset:

But the point of ?? is that it does the isset call for you. So try this, just put the values without using isset:

$resultInt = $array['intValue'] ?? -1;
$resultString = $array['stringValue'] ?? 'Another text';
$resultBool = $array['boolValue'] ?? true;

这篇关于PHP Null合并运算符混乱的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！