Smalltalk中的操作员可以超载吗? [英] Can operators in Smalltalk be overloaded?

问题描述

是否可以在Smalltalk中重载运算符?

Is it possible to overload operators in Smalltalk?

我正在寻找教程/示例.

I am looking for tutorials/examples.

谢谢.

推荐答案

在Smalltalk中，方法重载是不可能的.取而代之的是，方法重载和称为双重调度的技术的结合，用于实现与其他语言中的运算符重载相同的行为.

Method overloading is not possible in Smalltalk. Instead, a combination of method overriding and a technique called double dispatch is used to implement the same behavior as operator overloading in other languages.

您可以在数学运算符+,*,/,-(在Smalltalk中为二进制消息)中找到示例实现.这里的想法是:Integer>>+的实现向其参数发送一条消息#addWithInteger:. #addWithInteger:的实现是在每个Magnitude子类上实现的，以便专门添加Int + Int，Float + Int等...

You can find an example implementation in the mathematical operators +,*,/,- (which are binary messages in Smalltalk). Here is the idea: the implementation of Integer>>+ sends a message #addWithInteger: to its argument. The implementation of #addWithInteger: is implemented on each Magnitude subclass, such as to specialize addition of Int+Int, Float+Int, etc...

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