为什么表达式(0 == 0& 1 == 1)的计算结果为False? [英] Why is the expression (0==0 & 1==1) evaluating to False?

问题描述

类似地(-1 ==-1& 1 == 1)也为False.

Similarly (-1==-1 & 1==1) is also False.

很抱歉，这很明显，但是我找不到解释.

Apologies if this is something obvious but I can't find an explanation for it.

推荐答案

&是按位AND 运算符.如文档所述，按位运算符的优先级高于逻辑运算符，所以

& is the bitwise AND operator. As mentioned in the documentation, Bitwise operators have higher precedence than logical operators, so

0 == 0 & 1 == 1

成为

0 == (0 & 1) == 1

您可以想象它会从那里下坡:

And you can imagine it goes downhill from there:

   0 == (0 & 1) == 1
=> 0 == 0 == 1
=> 0 == 0 and 0 == 1
=> True and False 
=> False

假设您想要的是逻辑与，则实现此目标的python方法是使用and:

Assuming what you wanted was a logical AND, the python way to do that would be using and:

0 == 0 and 1 == 1

如您所愿，它将给您True.

这篇关于为什么表达式(0 == 0& 1 == 1)的计算结果为False?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！