静态隐式运算符 [英] Static implicit operator

问题描述

我最近找到了以下代码:

I recently found this code:

 public static implicit operator XElement(XmlBase xmlBase)
 {
     return xmlBase.Xml;
 }

static implicit operator是什么意思?

推荐答案

这是 转换运算符 .这意味着您可以编写以下代码:

This is a conversion operator. It means that you can write this code:

XmlBase myBase = new XmlBase();
XElement myElement = myBase;

编译器不会抱怨！在运行时，将执行转换运算符-将myBase作为参数传递，并返回有效的XElement作为结果.

And the compiler won't complain! At runtime, the conversion operator will be executed - passing myBase in as the argument, and returning a valid XElement as the result.

这是您作为开发人员告诉编译器的一种方式:

It's a way for you as a developer to tell the compiler:

即使它们看起来像是两种完全不相关的类型，实际上也存在一种从一种转换为另一种的方法；让我来处理如何做到这一点的逻辑."

"even though these look like two totally unrelated types, there is actually a way to convert from one to the other; just let me handle the logic for how to do it."

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