斯卡拉平等与类型检查? [英] Scala equality with type checking?

问题描述

是否存在用于执行类型检查相等性的统一方法? 不幸的是

Is there a uniform method to perform equality with type checking? Unfortunately

val objectA:String = "test"
val objectB:Int = 2
objectA == objectB

相等运算符==不会抱怨objectB是一个Int而objectA是一个String. 我需要像===这样的运算符也执行类型检查(并且我希望它对所有scala obj都是统一的).是否存在这样的运算符?

the equality operator == doesn't complain if objectB is a Int while objectA is a String. I would need an operator like === that perform type checking as well (and I hope it is uniform to all scala obj). Does such operator exist?

推荐答案

您需要查看 scalaz 的

You need to look at scalaz's === for type-safe equals - it's implemented as type class there.

您还可以通过 Heiko Seeberger 观看谈话，他在其中描述了其实现方式:

You can also watch talk by Heiko Seeberger, where he describes how it's implemented:

http://days2011.scala-lang.org/node/138/275

您还可以在此处找到一些示例:

You can also find some examples here:

(在示例中，他们使用的是≟方法，但这只是===的别名)

(in the examples they are using ≟ method, but it's simply alias for ===)

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