改进DNA比对解盖的代码设计 [英] Improving code design of DNA alignment degapping

问题描述

这是有关更有效的代码设计的问题:

This is a question regarding a more efficient code design:

假定代表两个基因(gene1和gene2)的三个对齐的DNA序列(seq1，seq2和seq3；它们都是字符串).相对于比对的DNA序列，这些基因的起始和终止位置是已知的.

Assume three aligned DNA sequences (seq1, seq2 and seq3; they are each strings) that represent two genes (gene1 and gene2). Start and stop positions of these genes are known relative to the aligned DNA sequences.

# Input
align = {"seq1":"ATGCATGC", # In seq1, gene1 and gene2 are of equal length
         "seq2":"AT----GC",
         "seq3":"A--CA--C"}
annos = {"seq1":{"gene1":[0,3], "gene2":[4,7]},
         "seq2":{"gene1":[0,3], "gene2":[4,7]},
         "seq3":{"gene1":[0,3], "gene2":[4,7]}}

我希望消除比对中的缺口(即破折号)，并保持基因起始和终止位置的相对关联.

I wish to remove the gaps (i.e., dashes) from the alignment and maintain the relative association of the start and stop positions of the genes.

# Desired output
align = {"seq1":"ATGCATGC", 
         "seq2":"ATGC",
         "seq3":"ACAC"}
annos = {"seq1":{"gene1":[0,3], "gene2":[4,7]},
         "seq2":{"gene1":[0,1], "gene2":[2,3]},
         "seq3":{"gene1":[0,1], "gene2":[2,3]}}

获得所需的输出看起来并不那么琐碎.下面，我针对此问题编写了一些(行编号)伪代码，但是肯定有更优雅的设计.

Obtaining the desired output is less trivial than it may seem. Below I wrote some (line-numbered) pseudocode for this problem, but surely there is a more elegant design.

1  measure length of any aligned gene  # take any seq, since all seqs aligned
2  list_lengths = list of gene lengths  # order is important
3  for seq in alignment
4      outseq = ""
5      for each num in range(0, length(seq))  # weird for-loop is intentional
6          if seq[num] == "-"
7              current_gene = gene whose start/stop positions include num
8              subtract 1 from length of current_gene
9              subtract 1 from lengths of all genes following current_gene in list_lengths
10         else
11             append seq[num] to outseq
12     append outseq to new variable
13     convert gene lengths into start/stop positions and append ordered to new variable

任何人都可以给我一些建议/示例，以进行更短，更直接的代码设计吗?

Can anyone give me suggestions/examples for a shorter, more direct code design?

推荐答案

此答案处理从注释到cdlanes答案的更新的annos词典.该答案使annos词典的seq2 gene2索引错误[2,1].如果序列在该区域中包含所有间隔，则我建议的解决方案将从字典中删除gene条目.还需要注意的是，如果一个基因在最后一个align中仅包含一个字母，那么anno[geneX]的起始和终止索引将相等->请从注释的annos中参见seq3 gene1.

This answer handles your updated annos dictionary from the comment to cdlanes answer. That answer leaves the annos dictionary with the incorrect index of [2,1] for seq2 gene2. My proposed solution will remove the gene entry from the dictionary if the sequence contains ALL gaps in that region. Also to note, if a gene contains only one letter in the final align, then anno[geneX] will have equal indices for start and stop --> See seq3 gene1 from your commented annos.

align = {"seq1":"ATGCATGC",
         "seq2":"AT----GC",
         "seq3":"A--CA--C"}

annos = {"seq1":{"gene1":[0,3], "gene2":[4,7]},
         "seq2":{"gene1":[0,3], "gene2":[4,7]},
         "seq3":{"gene1":[0,3], "gene2":[4,7]}}


annos3 = {"seq1":{"gene1":[0,2], "gene2":[3,4], "gene3":[5,7]}, 
          "seq2":{"gene1":[0,2], "gene2":[3,4], "gene3":[5,7]}, 
          "seq3":{"gene1":[0,2], "gene2":[3,4], "gene3":[5,7]}}

import re
for name,anno in annos.items():
    # indices of gaps removed usinig re
    removed = [(m.start(0)) for m in re.finditer(r'-', align[name])]

    # removes gaps from align dictionary
    align[name] = re.sub(r'-', '', align[name])

    build_dna = ''
    for gene,inds in anno.items():

        start_ind = len(build_dna)+1

        #generator to sum the num '-' removed from gene
        num_gaps = sum(1 for i in removed if i >= inds[0] and i <= inds[1])

        # build the de-gapped string
        build_dna+= align[name][inds[0]:inds[1]+1].replace("-", "")

        end_ind = len(build_dna)

        if num_gaps == len(align[name][inds[0]:inds[1]+1]): #gene is all gaps
            del annos[name][gene] #remove the gene entry
            continue
        #update the values in the annos dictionary
        annos[name][gene][0] = start_ind-1
        annos[name][gene][1] = end_ind-1

结果:

In [3]: annos
Out[3]:  {'seq1': {'gene1': [0, 3], 'gene2': [4, 7]},
          'seq2': {'gene1': [0, 1], 'gene2': [2, 3]},
          'seq3': {'gene1': [0, 1], 'gene2': [2, 3]}}

来自上述3个基因annos的结果.只需替换annos变量:

Results from the 3 gene annos above. Just replace the annos variable:

In [5]: annos3
Out[5]:  {'seq1': {'gene1': [0, 2], 'gene2': [3, 4], 'gene3': [5, 7]},
          'seq2': {'gene1': [0, 1], 'gene3': [2, 3]},
          'seq3': {'gene1': [0, 0], 'gene2': [1, 2], 'gene3': [3, 3]}}

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