根据其他选择值在选择中隐藏选项 [英] Hide option in select based on other select value
本文介绍了根据其他选择值在选择中隐藏选项的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
对于拼车网站,我有两个到达城市和离开城市的选择标签,我想防止用户在到达城市的选择中选择相同的城市,这里选择离开城市是一个示例:>
I have two select tags of arrival city and departure city for carpool web site, I want to prevent the user from selecting the same city in the select of arrival city and the select of the departure city here is an example :
<select name="departure" size="1">
<option value="1">NY</option>
<option value="2">FL</option>
<option value="3">LA</option>
</select>
<select name="arrival" size="1">
<option value="1">NY</option>
<option value="2">FL</option>
<option value="3">LA</option>
</select>
我只是想防止用户使用JavaScript或任何其他解决方案在两个选择字段中选择同一城市
I just want to prevent the user from selecting the same city in both select fields using JavaScript or any other solution
推荐答案
对于简单的解决方案,我建议:
For a simple solution, I'd suggest:
function deDupe(el) {
var opt = el.selectedIndex,
other = el.name == 'departure' ? document.getElementsByName('arrival')[0] : document.getElementsByName('departure')[0],
options = other.getElementsByTagName('option');
for (var i = 0, len = options.length; i < len; i++) {
options[i].disabled = i == opt ? true : false;
}
}
var departure = document.getElementsByName('departure')[0],
arrival = document.getElementsByName('arrival')[0];
deDupe(document.getElementsByName('departure')[0]);
departure.onchange = function () {
deDupe(departure);
};
arrival.onchange = function () {
deDupe(arrival);
};
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