PHP循环内循环，选择了选项? [英] PHP loop within a loop, option selected?

问题描述

使用PHP，我在这样的循环中回显表行:

Using PHP I echo out table rows in a loop like this:

<?php
/* SQL STUFF */

  while ($row = mysql_fetch_array($select_courseelements)) {
   echo "<tr>\n";
    echo "<td>".$row['scpe_name']."</td>\n";
    echo "<td>".$row['scpe_days']."</td>\n";
   echo "</tr>\n";
  }

现在，我想在循环运行的<td>中包括一个具有5个预定义的<option>值的<select>元素.选项value是1到5.

$row循环中还有一列，其值从1到5($row['scpe_grades_status']).

每当该值等于<select>中的值时，我都希望它将其更改为selected='selected'.

这可能吗?

Now I would like to include a <select> element with 5 predefined <option> values inside a <td> running with the loop. The option values will be 1 to 5.

There is also a column inside the $row loop that holds a value of 1 to 5 ($row['scpe_grades_status']).

Each time this value is equal to the one in the <select> I want it to change it to selected='selected'.

Would this be possible?

我的<select>在循环运行时看起来像这样:

My <select> will look something like this when it's beeing run in the loop:

echo "<td>\n";
echo "<select id='elements_grade'>\n";
        echo "<option value='1'>Registrerad</option>\n";
        echo "<option value='2'>Ej påbörjad</option>\n";
        echo "<option value='3'>Pågående</option>\n";
        echo "<option value='4'>Godkänd</option>\n";
        echo "<option value='5'>Deltagit</option>\n";
        echo "<option value='6'>Ej deltagit</option>\n";
echo "</select>\n";
echo "</td>\n";

推荐答案

$array = array('Registrerad' => 1, 'Ej påbörjad' => 2, 'Pågående' => 3, 'Godkänd' => 4, 'Deltagit' => 5, 'Ej deltagit' => 6);

foreach ($array as $key=>$value) {
    if ($value == $row['scpe_grades_status'])
        echo '<option value="'.$value.'" selected>'.$key.'</option>';
    else
        echo '<option value="'.$value.'">'.$key.'</option>';
}

类似的东西吗?

这篇关于PHP循环内循环，选择了选项?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！