怎么把Option [Try [_]]转换为Try [Option [_]]? [英] How to convert Option[Try[_]] to Try[Option[_]]?

问题描述

我经常使用下面的函数将Option[Try[_]]转换为Try[Option[_]]，但是感觉不对.可以用惯用的方式表达这种功能吗?

I quite often use the function below to convert Option[Try[_]] to Try[Option[_]] but it feels wrong. Can be such a functionality expressed in more idiomatic way?

def swap[T](optTry: Option[Try[T]]): Try[Option[T]] = {
  optTry match {
    case Some(Success(t)) => Success(Some(t))
    case Some(Failure(e)) => Failure(e)
    case None => Success(None)
  }
}

说我有两个值:

val v1: Int = ???
val v2: Option[Int] = ???

我想对这些值进行操作op(这可能会失败)，并将其传递给下面的函数f.

I want to make an operation op (which can fail) on these values and pass that to function f below.

def op(x: Int): Try[String]
def f(x: String, y: Option[String]): Unit

我通常用于理解以提高可读性:

I typically use for comprehension for readability:

for {
  opedV1 <- op(v1)
  opedV2 <- swap(v2.map(op))
} f(opedV1, opedV2)

PS.我想避免使用像scalaz这样的笨重的东西.

PS. I'd like to avoid some heavy stuff like scalaz.

推荐答案

像Try { option.map(_.get) }这样的声音将满足您的要求.

Sounds like Try { option.map(_.get) } will do what you want.

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