Oracle在所有表的所有列中搜索字符串 [英] Oracle Search all tables all columns for string

查看:141
本文介绍了Oracle在所有表的所有列中搜索字符串的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我需要在我们的oracle数据库中搜索所有表和列中的字符串.我在网上找到以下查询,但执行该查询时会收到以下错误

I need to search our oracle database for a string in all tables and columns. I have the below query I found online but when I execute it I get the following error

感谢您的帮助

ORA-06550: line 6, column 31:
PL/SQL: ORA-00904: "COLUMN_NAME": invalid identifier
ORA-06550: line 6, column 12:
PL/SQL: SQL Statement ignored
ORA-06550: line 8, column 30:
PLS-00364: loop index variable 'T' use is invalid
ORA-06550: line 7, column 4:
PL/SQL: Statement ignored
ORA-06550: line 12, column 38:
PLS-00364: loop index variable 'T' use is invalid
ORA-06550: line 12, column 16:
PL/SQL: Statement ignored

BEGIN  
  FOR t IN (SELECT table_name, column_name FROM all_tables) LOOP   
   EXECUTE IMMEDIATE    
    'SELECT COUNT(*) FROM '||t.table_name||' WHERE '||t.column_name||' = :1'   
     INTO match_count  
       USING v_search_string; 
          IF match_count > 0 THEN 
               dbms_output.put_line( t.table_name ||' '||t.column_name||' '||match_count );
           END IF; 
  END LOOP;
END;
/

推荐答案

至少,您需要查询ALL_TAB_COLUMNS,而不是ALL_TABLES

At a minimum, you need to query ALL_TAB_COLUMNS, not ALL_TABLES

DECLARE
  match_count integer;
  v_search_string varchar2(4000) := <<string you want to search for>>;
BEGIN  
  FOR t IN (SELECT owner, table_name, column_name FROM all_tab_columns) LOOP   
    EXECUTE IMMEDIATE    
      'SELECT COUNT(*) FROM '||t.owner || '.' || t.table_name||
      ' WHERE '||t.column_name||' = :1'   
       INTO match_count  
      USING v_search_string; 
    IF match_count > 0 THEN 
      dbms_output.put_line( t.owner || '.' || t.table_name ||' '||t.column_name||' '||match_count );
    END IF; 
  END LOOP;
END;
/

但是,如果您要查找字符串,则几乎可以肯定希望将自己限制为查找可以存储字符串的列.例如,在DATE列中搜索字符串是没有意义的.并且,除非您对BLOB列包含的内容有充分的先验知识,并且能够解析BLOB列的二进制格式,否则在BLOB列中搜索字符串是没有意义的.鉴于此,我怀疑您想要更多类似的东西

If you are looking for a string, however, you would almost certainly want to restrict yourself to looking for columns that could store a string. It wouldn't make sense, for example, to search a DATE column for a string. And unless you have a great deal of a priori knowledge about what a BLOB column contains and the ability to parse the BLOB column's binary formatting, it wouldn't make sense to search a BLOB column for a string. Given that, I suspect you want something more like

DECLARE
  match_count integer;
  v_search_string varchar2(4000) := <<string you want to search for>>;
BEGIN  
  FOR t IN (SELECT owner,
                   table_name, 
                   column_name 
              FROM all_tab_columns
             WHERE data_type in ('CHAR', 'VARCHAR2', 'NCHAR', 'NVARCHAR2', 
                                 'CLOB', 'NCLOB') ) 
  LOOP   
    BEGIN
      EXECUTE IMMEDIATE    
        'SELECT COUNT(*) FROM '||t.owner || '.' || t.table_name||
        ' WHERE '||t.column_name||' = :1'   
         INTO match_count  
        USING v_search_string; 
      IF match_count > 0 THEN 
        dbms_output.put_line( t.owner || '.' || t.table_name ||' '||t.column_name||' '||match_count );
      END IF; 
    EXCEPTION
      WHEN others THEN
        dbms_output.put_line( 'Error encountered trying to read ' ||
                              t.column_name || ' from ' || 
                              t.owner || '.' || t.table_name );
    END;
  END LOOP;
END;
/

当然,这将非常慢-您将对表中的每个字符串列全扫描一次.对于中等大小的表和中等数量的字符串列,这可能会花费相当长的时间.

Of course, this is going to be insanely slow-- you'd full scan every table once for every string column in the table. With moderately large tables and a moderate number of string columns, that is likely to take quite a while.

这篇关于Oracle在所有表的所有列中搜索字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆