Oracle在所有表的所有列中搜索字符串 [英] Oracle Search all tables all columns for string
问题描述
我需要在我们的oracle数据库中搜索所有表和列中的字符串.我在网上找到以下查询,但执行该查询时会收到以下错误
I need to search our oracle database for a string in all tables and columns. I have the below query I found online but when I execute it I get the following error
感谢您的帮助
ORA-06550: line 6, column 31:
PL/SQL: ORA-00904: "COLUMN_NAME": invalid identifier
ORA-06550: line 6, column 12:
PL/SQL: SQL Statement ignored
ORA-06550: line 8, column 30:
PLS-00364: loop index variable 'T' use is invalid
ORA-06550: line 7, column 4:
PL/SQL: Statement ignored
ORA-06550: line 12, column 38:
PLS-00364: loop index variable 'T' use is invalid
ORA-06550: line 12, column 16:
PL/SQL: Statement ignored
BEGIN
FOR t IN (SELECT table_name, column_name FROM all_tables) LOOP
EXECUTE IMMEDIATE
'SELECT COUNT(*) FROM '||t.table_name||' WHERE '||t.column_name||' = :1'
INTO match_count
USING v_search_string;
IF match_count > 0 THEN
dbms_output.put_line( t.table_name ||' '||t.column_name||' '||match_count );
END IF;
END LOOP;
END;
/
推荐答案
至少,您需要查询ALL_TAB_COLUMNS,而不是ALL_TABLES
At a minimum, you need to query ALL_TAB_COLUMNS, not ALL_TABLES
DECLARE
match_count integer;
v_search_string varchar2(4000) := <<string you want to search for>>;
BEGIN
FOR t IN (SELECT owner, table_name, column_name FROM all_tab_columns) LOOP
EXECUTE IMMEDIATE
'SELECT COUNT(*) FROM '||t.owner || '.' || t.table_name||
' WHERE '||t.column_name||' = :1'
INTO match_count
USING v_search_string;
IF match_count > 0 THEN
dbms_output.put_line( t.owner || '.' || t.table_name ||' '||t.column_name||' '||match_count );
END IF;
END LOOP;
END;
/
但是,如果您要查找字符串,则几乎可以肯定希望将自己限制为查找可以存储字符串的列.例如,在DATE列中搜索字符串是没有意义的.并且,除非您对BLOB列包含的内容有充分的先验知识,并且能够解析BLOB列的二进制格式,否则在BLOB列中搜索字符串是没有意义的.鉴于此,我怀疑您想要更多类似的东西
If you are looking for a string, however, you would almost certainly want to restrict yourself to looking for columns that could store a string. It wouldn't make sense, for example, to search a DATE column for a string. And unless you have a great deal of a priori knowledge about what a BLOB column contains and the ability to parse the BLOB column's binary formatting, it wouldn't make sense to search a BLOB column for a string. Given that, I suspect you want something more like
DECLARE
match_count integer;
v_search_string varchar2(4000) := <<string you want to search for>>;
BEGIN
FOR t IN (SELECT owner,
table_name,
column_name
FROM all_tab_columns
WHERE data_type in ('CHAR', 'VARCHAR2', 'NCHAR', 'NVARCHAR2',
'CLOB', 'NCLOB') )
LOOP
BEGIN
EXECUTE IMMEDIATE
'SELECT COUNT(*) FROM '||t.owner || '.' || t.table_name||
' WHERE '||t.column_name||' = :1'
INTO match_count
USING v_search_string;
IF match_count > 0 THEN
dbms_output.put_line( t.owner || '.' || t.table_name ||' '||t.column_name||' '||match_count );
END IF;
EXCEPTION
WHEN others THEN
dbms_output.put_line( 'Error encountered trying to read ' ||
t.column_name || ' from ' ||
t.owner || '.' || t.table_name );
END;
END LOOP;
END;
/
当然,这将非常慢-您将对表中的每个字符串列全扫描一次.对于中等大小的表和中等数量的字符串列,这可能会花费相当长的时间.
Of course, this is going to be insanely slow-- you'd full scan every table once for every string column in the table. With moderately large tables and a moderate number of string columns, that is likely to take quite a while.
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