Oracle:使用ROWNUM和ORDER BY子句一起更新表列 [英] Oracle: Updating a table column using ROWNUM in conjunction with ORDER BY clause

查看:496
本文介绍了Oracle:使用ROWNUM和ORDER BY子句一起更新表列的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想用一个运行中的整数填充一个表列,所以我正在考虑使用ROWNUM.但是,我需要根据其他列的顺序填充它,例如ORDER BY column1, column2.不幸的是,这是不可能的,因为Oracle不接受以下语句:

I want to populate a table column with a running integer number, so I'm thinking of using ROWNUM. However, I need to populate it based on the order of other columns, something like ORDER BY column1, column2. That is, unfortunately, not possible since Oracle does not accept the following statement:

UPDATE table_a SET sequence_column = rownum ORDER BY column1, column2;

也不执行以下语句(尝试使用WITH子句):

Nor the following statement (an attempt to use WITH clause):

WITH tmp AS (SELECT * FROM table_a ORDER BY column1, column2)
UPDATE tmp SET sequence_column = rownum;

那么我该如何使用SQL语句而不在PL/SQL中使用游标迭代方法呢?

So how do I do it using an SQL statement and without resorting to cursor iteration method in PL/SQL?

推荐答案

这应该有效(对我有用)

This should work (works for me)

update table_a outer 
set sequence_column = (
    select rnum from (

           -- evaluate row_number() for all rows ordered by your columns
           -- BEFORE updating those values into table_a
           select id, row_number() over (order by column1, column2) rnum  
           from table_a) inner 

    -- join on the primary key to be sure you'll only get one value
    -- for rnum
    where inner.id = outer.id);

或者您使用MERGE语句.像这样的东西.

OR you use the MERGE statement. Something like this.

merge into table_a u
using (
  select id, row_number() over (order by column1, column2) rnum 
  from table_a
) s
on (u.id = s.id)
when matched then update set u.sequence_column = s.rnum

这篇关于Oracle:使用ROWNUM和ORDER BY子句一起更新表列的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆