oracle SQL如何从日期中删除时间 [英] oracle SQL how to remove time from date

问题描述

我有一个名为StartDate的列，其中包含以下格式的日期:03-03-2012 15:22

I have a column named StartDate containing a date in this format: 03-03-2012 15:22

我需要将其转换为日期.它应该看起来像这样:DD/MM/YYYY

What I need is to convert it to date. It should be looking like this: DD/MM/YYYY

我没有成功尝试过的是:

What I have tried without success is:

select 
p1.PA_VALUE as StartDate,
p2.PA_VALUE as EndDate
from WP_Work p 
LEFT JOIN PARAMETER p1 on p1.WP_ID=p.WP_ID AND p1.NAME = 'StartDate'
LEFT JOIN PARAMETER p2 on p2.WP_ID=p.WP_ID AND p2.NAME = 'Date_To'
WHERE p.TYPE = 'EventManagement2'
AND TO_DATE(p1.PA_VALUE, 'DD/MM/YYYY') >= TO_DATE('25/10/2012', 'DD/MM/YYYY')
AND TO_DATE(p2.PA_VALUE, 'DD/MM/YYYY') <= TO_DATE('26/10/2012', 'DD/MM/YYYY')

有没有办法做到这一点?

Is there a way to do this?

PA_VALUE列为:VARCHAR2

推荐答案

将字符串转换为日期时，需要将日期掩码与字符串中的格式匹配.其中包括一个时间元素，您需要通过截断将其删除:

When you convert your string to a date you need to match the date mask to the format in the string. This includes a time element, which you need to remove with truncation:

select 
    p1.PA_VALUE as StartDate,
    p2.PA_VALUE as EndDate
from WP_Work p 
LEFT JOIN PARAMETER p1 on p1.WP_ID=p.WP_ID AND p1.NAME = 'StartDate'
LEFT JOIN PARAMETER p2 on p2.WP_ID=p.WP_ID AND p2.NAME = 'Date_To'
WHERE p.TYPE = 'EventManagement2'
AND trunc(TO_DATE(p1.PA_VALUE, 'DD-MM-YYYY HH24:MI')) >= TO_DATE('25/10/2012', 'DD/MM/YYYY')
AND trunc(TO_DATE(p2.PA_VALUE, 'DD-MM-YYYY HH24:MI')) <= TO_DATE('26/10/2012', 'DD/MM/YYYY')

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