XML Oracle:多个子节点摘录 [英] XML Oracle : Multiple Child Node extract
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问题描述
我有一个xml代码:
<begin>
<entry>
<lastname>gordon</lastname>
<NumberList>
<number>100</number>
<codelist>
<code>213</code>
<code>214</code>
<codelist>
<login>
<user>user1</user>
<user>user2</user>
</login>
<NumberList>
<address>
<addresslist>Jl. jalan pelan-pelan ke Bekasi, Indonesia</addresslist>
</address>
</entry>
<entry>
<lastname>mark</lastname>
<address>
<addresslist>Jl. jalan cepet-cepet ke Jakarta, Indonesia</addresslist>
</address>
</entry>
</begin>
我的代码:
FOR r IN (SELECT VALUE(p) col_val,
EXTRACT(VALUE(P), '/entry/codelist') AS code,
EXTRACT(VALUE(P), '/entry/login') AS login
FROM TABLE(XMLSequence(Extract(x,'/begin/entry'))) p)
LOOP
IF r.col_val.existsnode('/entry/lastname/text()') > 0
THEN
vc_lastname := r.col_val.extract('/sdnEntry/lastname/text()').getstringval();
END IF;
IF r.col_val.existsnode('/entry/address/addresslist/text()') > 0
THEN
vc_address := r.col_val.extract('/sdnEntry/address/addresslist/text()').getstringval();
END IF;
IF r.col_val.existsnode('/entry/codelist/id/code/text()') > 0 AND r.col_val.existsnode('/entry/login/user/text()') > 0
THEN
FOR R1 IN (SELECT EXTRACTVALUE(VALUE(T1), '/codelist/code/text()') AS code
FROM TABLE(XMLSEQUENCE(EXTRACT(R.code, '/codelist'))) T1)
LOOP
DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName||' - '||R1.code||' - '||R2.address);
END LOOP;
FOR R2 IN (SELECT
EXTRACTVALUE(VALUE(T1), '/login/user/text()') AS user
FROM TABLE(XMLSEQUENCE(EXTRACT(R.address, 'login/'))) T1)
LOOP
DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName||' - '||R2.user||' - '||R2.address);
END LOOP;
ELSE
DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName);
END IF;
我的问题:如何循环子节点，以便数据变得像这样:
LastName | Number | code | user | address
gordon | 100 | 213 | user1 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon | 100 | 213 | user2 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon | 100 | 214 | user1 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon | 100 | 214 | user2 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
mark | Null | null | null |Jl. jalan cepet-cepet ke Jakarta, Indonesia
任何帮助将不胜感激.
解决方案
您可以使用XMLTable()函数来获得所需的结果:
select q.Lastname
, q.Numberid
, s.codeid
, w.LoginId
, q.address
from t1 t
left join xmltable('/begin/entry'
passing t.xml_col
columns LastName varchar2(21) path 'lastname',
NumberId number path 'NumberList/number',
Address varchar2(201) path 'address/addresslist',
CodeList XmlType Path 'NumberList/codelist/code',
Logins XmlType Path 'NumberList/login/user'
) q
on (1=1)
left join xmltable('/code'
passing q.CodeList
columns CodeId number path '.') s
on (1=1)
left join xmltable('/user'
passing q.Logins
columns LoginId varchar2(11) path '.') w
on (1=1)
结果: SQLFiddle演示
Lastname Numberid Codeid Loginid Address
---------------------------------------------------------------------------
gordon 100 213 user1 Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon 100 213 user2 Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon 100 214 user1 Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon 100 214 user2 Jl. jalan pelan-pelan ke Bekasi, Indonesia
mark null null null Jl. jalan cepet-cepet ke Jakarta, Indonesia
注意:使用11.2.0.2之前的Oracle版本时，当cursor_sharing参数设置为FORCE时，某些类型的XML查询可能会遇到ORA-1780 error(错误8545377). SIMILAR(从11.2开始弃用).将cursor_sharing参数设置为EXACT(默认值)将解决此问题.
I have an xml code :
<begin>
<entry>
<lastname>gordon</lastname>
<NumberList>
<number>100</number>
<codelist>
<code>213</code>
<code>214</code>
<codelist>
<login>
<user>user1</user>
<user>user2</user>
</login>
<NumberList>
<address>
<addresslist>Jl. jalan pelan-pelan ke Bekasi, Indonesia</addresslist>
</address>
</entry>
<entry>
<lastname>mark</lastname>
<address>
<addresslist>Jl. jalan cepet-cepet ke Jakarta, Indonesia</addresslist>
</address>
</entry>
</begin>
my code:
FOR r IN (SELECT VALUE(p) col_val,
EXTRACT(VALUE(P), '/entry/codelist') AS code,
EXTRACT(VALUE(P), '/entry/login') AS login
FROM TABLE(XMLSequence(Extract(x,'/begin/entry'))) p)
LOOP
IF r.col_val.existsnode('/entry/lastname/text()') > 0
THEN
vc_lastname := r.col_val.extract('/sdnEntry/lastname/text()').getstringval();
END IF;
IF r.col_val.existsnode('/entry/address/addresslist/text()') > 0
THEN
vc_address := r.col_val.extract('/sdnEntry/address/addresslist/text()').getstringval();
END IF;
IF r.col_val.existsnode('/entry/codelist/id/code/text()') > 0 AND r.col_val.existsnode('/entry/login/user/text()') > 0
THEN
FOR R1 IN (SELECT EXTRACTVALUE(VALUE(T1), '/codelist/code/text()') AS code
FROM TABLE(XMLSEQUENCE(EXTRACT(R.code, '/codelist'))) T1)
LOOP
DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName||' - '||R1.code||' - '||R2.address);
END LOOP;
FOR R2 IN (SELECT
EXTRACTVALUE(VALUE(T1), '/login/user/text()') AS user
FROM TABLE(XMLSEQUENCE(EXTRACT(R.address, 'login/'))) T1)
LOOP
DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName||' - '||R2.user||' - '||R2.address);
END LOOP;
ELSE
DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName);
END IF;
My problem : How to loop child nodes so the data will become like this :
LastName | Number | code | user | address
gordon | 100 | 213 | user1 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon | 100 | 213 | user2 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon | 100 | 214 | user1 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon | 100 | 214 | user2 |Jl. jalan pelan-pelan ke Bekasi, Indonesia
mark | Null | null | null |Jl. jalan cepet-cepet ke Jakarta, Indonesia
Any help would be appreciate.
解决方案
You can achieve desired result by using XMLTable() function:
select q.Lastname
, q.Numberid
, s.codeid
, w.LoginId
, q.address
from t1 t
left join xmltable('/begin/entry'
passing t.xml_col
columns LastName varchar2(21) path 'lastname',
NumberId number path 'NumberList/number',
Address varchar2(201) path 'address/addresslist',
CodeList XmlType Path 'NumberList/codelist/code',
Logins XmlType Path 'NumberList/login/user'
) q
on (1=1)
left join xmltable('/code'
passing q.CodeList
columns CodeId number path '.') s
on (1=1)
left join xmltable('/user'
passing q.Logins
columns LoginId varchar2(11) path '.') w
on (1=1)
Result: SQLFiddle Demo
Lastname Numberid Codeid Loginid Address
---------------------------------------------------------------------------
gordon 100 213 user1 Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon 100 213 user2 Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon 100 214 user1 Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon 100 214 user2 Jl. jalan pelan-pelan ke Bekasi, Indonesia
mark null null null Jl. jalan cepet-cepet ke Jakarta, Indonesia
Find out more about XMLTable() function.
Note: Working with Oracle releases prior to 11.2.0.2, you can encounter ORA-1780 error(bug 8545377) on certain types of XML queries when cursor_sharing parameter is set to FORCE or SIMILAR(deprecated starting from 11.2). Setting cursor_sharing parameter to EXACT(default value), will solve the problem.
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