将to_char(myDate,'DAY')的结果与字符串进行比较时出现的问题 [英] Issue when comparing result of to_char(myDate, 'DAY') to a string
问题描述
我一直在试图找出问题所在,但是我很不幸,根本不了解这个问题.我有以下代码:
I have been trying to find what the issue might be but I am just out of luck and don't understand this problem at all.I have the following code:
CREATE OR REPLACE FUNCTION ckeckDay(dateC in date)
RETURN VARCHAR
IS
day VARCHAR(15);
checkFriday VARCHAR(1);
BEGIN
checkFriday := 'N';
day := to_char(dateC, 'DAY');
IF day = 'FRIDAY' THEN
checkFriday := 'Y';
END IF;
RETURN day;
END;
/
dateC
设置为星期五(甚至通过返回day
而不是day
变量对其进行了测试,然后返回星期五.)但是,即使day
变量,IF
语句也永远不会求值为true确实是星期五.任何想法都可以解决这个问题.谢谢
the dateC
is set to Friday (even tested it by returning day
instead of the day
variable and it returns Friday.) However the IF
statement never evaluates to true even though the day
variable is indeed Friday.Any ideas how to go around this issue.Thanks
推荐答案
这是因为day
变量包含空白填充值.使用trim
函数消除前导和尾随空格:
It is because day
variable contains a blank padded value. Use trim
function to get rid of leading and trailing spaces:
IF trim(day) = 'FRIDAY' THEN
checkFriday := 'Y';
END IF;
并且对于字符串变量,请使用VARCHAR2
数据类型.请勿使用VARCHAR
.
And please use VARCHAR2
datatype for string variables. Do not use VARCHAR
.
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