Oracle，将持续时间行除以一小时 [英] Oracle, split a time duration row by one hour period

问题描述

我正在研究oracle db，但我不太擅长Oracle. 我正在尝试按一个小时的时间段分隔行.

I'm working on oracle db and I'm not quite good at Oracle. I'm trying to split a row by one hour period.

例如，如果一个时间行如下所示，

For example, if a time row has given as below,

开始时间(yyyy/mm/dd hh24:mi:ss)|结束时间(yyyy/mm/dd hh24:mi:ss)

Start_time(yyyy/mm/dd hh24:mi:ss) | End_time(yyyy/mm/dd hh24:mi:ss)

2013/09/01 09:30:00         2013/09/01 11:38:59

我想要看到的结果:

2013/09/01 09:30:00         2013/09/01 09:59:59  
2013/09/01 10:00:00         2013/09/01 10:59:59
2013/09/01 11:00:00         2013/09/01 11:38:59

我已经被搜索过如何做，但找不到.
但是我想可以通过使用"CONNECT BY"来完成.
任何帮助将是巨大的.提前致谢.

I've been searched how to do it but I couldn't find one.
But I guess It can be done by using 'CONNECT BY'.
Any help will be great. Thanks in advance.

推荐答案

我有一个基本查询，您可以解决该问题并获得所需的内容.

I have bulit a basic query, you can work around it and get what you want.

select greatest(Start_time, trunc(Start_time+(level-1)/24, 'hh24')), 
least(End_time, trunc(Start_time+(level)/24, 'hh24'))
from log_table 
connect by level <= floor((dt1-dt2)*24)+1;

sqlfiddle示例:

Example at sqlfiddle:

http://sqlfiddle.com/#!4/82625/29

这篇关于Oracle，将持续时间行除以一小时的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！