在Oracle SQL中将IPv4地址拆分为4个数字 [英] Split IPv4 address into 4 numbers in Oracle sql

问题描述

我正在尝试将给定的IPv4地址分成四个数字.

I'm trying to split a given IPv4 address into four numbers.

在SQL Server中，此查询对我来说效果很好:

In SQL Server this query works well for me:

select CAST (PARSENAME('10.20.30.40',4) AS INT) 

结果:10

select CAST (PARSENAME('10.20.30.40',3) AS INT)

结果:20

以此类推.

我需要Oracle SQL中的等效语法，但找不到它.有什么主意吗?

I need the equivalent syntax in Oracle SQL, but can't find it. Any idea?

推荐答案

您可以使用regexp_substr:

select ip,
       regexp_substr(ip, '\d+',1,1) as first_octet,
       regexp_substr(ip, '\d+',1,2) as second_octet,
       regexp_substr(ip, '\d+',1,3) as third_octet,
       regexp_substr(ip, '\d+',1,4) as fourth_octet
from  (select '10.20.30.40' AS ip from dual )ips;

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